In this post, I am explaining how can you check the similarity between two strings in terms of percentage in C# ? To check similarity between two strings we have formula by which we can find similarity in %.
In my previous posts, I explained Create Hindi TextBox Using Google Transliteration in ASP.Net, Convert Multipage Tiff file into PDF in ASP.Net using C#, Send mail in ASP.Net, Convert DataTable into List, Constructor Chainning in C#, Convert a Generic List to a Datatable, Get Property Names using Reflection in C#, Check Internet Connection using C#, SQL Server Database BackUp using C# and some other articles related to C#, ASP.Net, jQuery, Java Script and SQL Server.
The formula to check the similarity between two strings in % is-
Let's see some example-
C# Code
Similarity in % between Strings
Similarity in % between Arrays of String
Similarity in % between String Sentences
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In my previous posts, I explained Create Hindi TextBox Using Google Transliteration in ASP.Net, Convert Multipage Tiff file into PDF in ASP.Net using C#, Send mail in ASP.Net, Convert DataTable into List, Constructor Chainning in C#, Convert a Generic List to a Datatable, Get Property Names using Reflection in C#, Check Internet Connection using C#, SQL Server Database BackUp using C# and some other articles related to C#, ASP.Net, jQuery, Java Script and SQL Server.
The formula to check the similarity between two strings in % is-
Similarity (%) = 100 * (CommonItems * 2) / (Length of String1 + Length of String2)
Let's see some example-
C# Code
Similarity in % between Strings
1 2 3 4 5 6 7 8 9 10 11 12 | public static void SmilarityinPercentage() { string string1 = "Manish" ; string string2 = "Mahesh" ; char [] charString1 = string1.ToCharArray(); char [] charString2 = string2.ToCharArray(); var strCommon = charString1.Intersect(charString2); //Formula : Similarity (%) = 100 * (CommonItems * 2) / (Length of String1 + Length of String2) double Similarity = ( double )(100 * (strCommon.Count() * 2)) / (charString1.Length + charString2.Length); Console.WriteLine( "Strings are {0}% similar" , Similarity.ToString( "0.00" )); } //Output:- Strings are 66.67% similar |
Similarity in % between Arrays of String
1 2 3 4 5 6 7 8 9 10 | public void SmilarityinPercentage() { string [] string1 = new string [] { "Manish" , "Dubey" , "Dot" , "Net" , "World" }; string [] string2 = new string [] { "Dot" , "Net" , "World" }; var strCommon = string1.Intersect(string2); //Formula : Similarity (%) = 100 * (CommonItems * 2) / (Length of String1 + Length of String2) double Similarity = ( double )(100 * (strCommon.Count() * 2)) / (string1.Length + string2.Length); Console.WriteLine( "Strings are {0}% similar" , Similarity.ToString( "0.00" )); } //Output:- Strings are 75.00% similar |
Similarity in % between String Sentences
1 2 3 4 5 6 7 8 9 10 11 12 | public void SmilarityinPercentage() { string string1 = "My blog name is Dot Net World" ; string string2 = "Dot Net World" ; string [] splitString1 = string1.Split( ' ' ); string [] splitString2 = string2.Split( ' ' ); var strCommon = splitString1.Intersect(splitString2); //Formula : Similarity (%) = 100 * (CommonItems * 2) / (Length of String1 + Length of String2) double Similarity = ( double )(100 * (strCommon.Count() * 2)) / (splitString1.Length + splitString2.Length); Console.WriteLine( "Strings are {0}% similar" , Similarity.ToString( "0.00" )); } //Output:- Strings are 60.00% similar |
I hope you enjoyed this post. I would like to have any feedback from you. Your valuable feedback, question, or comments about this article are always welcome.
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